Chemistry 0620 · IGCSE · Ions and ionic bonds

Ions and ionic bonds — practice question

Silver bromide, AgBr, is formed when aqueous silver ethanoate, CH$_3$COOAg, is mixed with aqueous sodium bromide, NaBr. Equation 1 shows the reaction. $\text{CH}_3\text{COOAg}+\text{NaBr}\rightarrow\text{CH}_3\text{COONa}+\text{AgBr}$ The procedure is as follows. step 1 Place 200.0 cm$^3$ of 0.0500 mol dm$^{-3}$ CH$_3$COOAg in a beaker. That volume contains 0.0100 mol of Ag$^+$ ions. step 2 Add 50.0 cm$^3$ of aqueous NaBr. That volume contains 0.0100 mol of Br$^-$ ions. A precipitate is produced. step 3 Separate the mixture by filtration. step 4 Leave the solid residue to dry until every trace of water has gone. step 5 Measure the mass of the dried residue.
(a)[1]

Complete the ionic equation for the reaction by inserting the missing state symbols. Ag$^+$(.....) + Br$^-$(.....) → AgBr(.....)

(b)[1]

Name another aqueous silver salt that could be used in step 1.

(c)[1]

Use the details in step 2 to calculate the concentration of aqueous NaBr.

(d)[1]

State the colour of the precipitate formed in step 2.

(e)[3]

Use the information in step 1, step 2 and equation 1 to find the number of moles of AgBr formed. Then use this value to calculate the mass of AgBr formed.

(f)[1]

Name the salt that is dissolved in the filtrate in step 3.

(g(i))[1]

Suggest the missing step.

(g(ii))[1]

Name the substance that causes the larger mass of the dry residue.

(h(i))[2]

Suggest two aqueous solutions which can be combined to produce barium sulfate.

(h(ii))[2]

Write the balanced symbol equation for the reaction.

Worked solution & mark scheme

This 14-mark question has a full step-by-step worked solution and mark scheme. One marking point: The equation is Ag⁺(aq) + Br⁻(aq) → AgBr(s).

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