(a)[3]
Compare the basic strengths of ammonia, cyclohexylamine and phenylamine, and justify your answer.
(b(i))[1]
Name the mechanism shown for the reaction.
(b(ii))[4]
Complete the mechanism for the reaction of cyclohexylamine with $\text{CH}_3\text{COCl}$. $\text{R-NH}_2$ is used to stand for cyclohexylamine. Show all relevant lone pairs of electrons, curly arrows, charges and partial charges.
(b(iii))[1]
Cyclohexylamine reacts with an excess of $\text{CH}_3\text{COCl}$ to form compound M. Compound M has the molecular formula $\text{C}_{10}\text{H}_{17}\text{NO}_2$. Suggest and draw the structure of M.