A lorry (truck) is stationary on a straight, level road. A steady driving force of $5.4 \times 10^4\,\text{N}$ acts on the lorry, causing it to accelerate forwards.
(a)[2]
Define what is meant by ‘acceleration’.
(b(i))[1]
State the equation that gives work done. Make reference to the direction in which the force acts.
(b(ii))[2]
Calculate the work done on the lorry by the driving force when the lorry moves a distance of $280\,\text{m}$.
(b(iii))[3]
At a particular point on the road, the lorry has kinetic energy of $3.2 \times 10^6\,\text{J}$ and its speed is $12\,\text{m s}^{-1}$. Calculate the mass of the lorry.
Worked solution & mark scheme
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “variation / increase of velocity (with time)” …