A box of mass $4.0\,\text{kg}$ starts from rest and is pulled across a horizontal floor by a constant force $F$. A constant frictional force of $1.0\,\text{N}$ acts opposite the motion on the box. Once the box has moved $1.0\,\text{m}$, its velocity is $1.5\,\text{m s}^{-1}$. The box's kinetic energy is equal to the work done on it. Determine force $F$?
- A$2.0\,\text{N}$
- B$3.5\,\text{N}$
- C$4.0\,\text{N}$
- D$5.5\,\text{N}$