The specific heat capacity of lead is $130\ \text{J kg}^{-1}\,^{\circ}\text{C}^{-1}$. A lead sample with mass $0.50\ \text{kg}$ is raised from $10^{circ}\text{C}$ to $35^{\circ}\text{C}$. Which calculation gives the amount of thermal energy, in J, absorbed by the lead?
- A$0.50 \times 130 \times 25$
- B$0.50 \times 130 \times 35$
- C$\frac{0.50 \times 130}{25}$
- D$\frac{0.50 \times 130}{35}$