Physics 5054 · O Level · Specific heat capacity

Specific heat capacity — practice question

The specific heat capacity of lead is $130\ \text{J kg}^{-1}\,^{\circ}\text{C}^{-1}$. A lead sample with mass $0.50\ \text{kg}$ is raised from $10^{circ}\text{C}$ to $35^{\circ}\text{C}$. Which calculation gives the amount of thermal energy, in J, absorbed by the lead?

  • A$0.50 \times 130 \times 25$
  • B$0.50 \times 130 \times 35$
  • C$\frac{0.50 \times 130}{25}$
  • D$\frac{0.50 \times 130}{35}$

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