Physics 5054 · O Level · Pressure

Pressure — practice question

One end of a curved glass tube is open, while the other end is sealed. A dense liquid is poured into the tube, which traps air at the closed end. Figure 3.1 shows the tube, the liquid and the trapped air.
(a)[3]

The separation between the liquid levels is $h$. For room temperature, $h$ is 0.57 m. The liquid density is $1.4 \times 10^4\,\text{kg m}^{-3}$. The gravitational field strength $g$ is $10\,\text{N kg}^{-1}$ and atmospheric pressure is $1.0 \times 10^5\,\text{Pa}$. Calculate the pressure of the trapped air.

(b(i))[3]

The trapped air height in the tube is $x$. Explain, in molecular terms, why $x$ changes when the air is heated.

(b(ii))[2]

The trapped air settles to a constant temperature above its original temperature. Describe and explain how $h$ changes in terms of the pressures involved.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: Use either $\Delta p=\rho gh$ OR $0.57 \times 1.4 \times 10^4 \times 10$.

  • Full mark scheme, point by point
  • Step-by-step worked solution
  • Write your answer & get it marked instantly by AI