Use the metre rule to read the positions of points A and B shown in Fig. 1.1. Record your values to the nearest $0.1\,\text{cm}$. Position of point A = [BLANK] cm. Position of point B = [BLANK] cm.
In Fig. 1.1, the length $l$ is the separation between points A and B. The mean diameter $d$ of one ball may be determined from the equation $l = 6d$. Use your responses to (a)(i) to work out the length $l$ and the diameter $d$. Give both answers to the nearest $0.1\,\text{cm}$. $l = [BLANK]\,\text{cm}$, $d = [BLANK]\,\text{cm}$.
The mean volume $V$ of one glass ball by this method is given by the equation $V = \frac{3.14d^3}{6}$. Calculate $V$.
Figure 1.2 shows the volume of water in the measuring cylinder as $V_1$. Write down the reading $V_1$.
The six glass balls are then added carefully to the water in the measuring cylinder. Figure 1.3 shows the new reading on the measuring cylinder, $V_2$. The volume $V_T$ of the six balls is found from $V_T = V_2 - V_1$. Calculate $V_T$. Show your working.
Calculate the average volume $V$ of one ball by this method. Give your answer to the nearest $0.1\,\text{cm}^3$.
Suggest whether method 1 or method 2 gives the more accurate value for the volume of the ball. Explain your answer.
The student now uses the six glass balls to determine the average mass of one glass ball with a small beaker and a top pan (electronic) balance. Describe the method the student uses.