Physics 5054 · O Level · Momentum

Momentum — practice question

Fig. 3.1 depicts a firefighter aiming a jet of water at a wall. Diagram labels: firefighter, jet of water, wall, water. In 1.0 s, a horizontal volume of $7.5 \times 10^{-3}\,\text{m}^3$ of water reaches the wall at a speed of 24 m/s. The density of water is 1000 kg/m$^3$.
(a(i))[2]

Calculate the mass of water striking the wall in 1.0 s.

(a(ii))[2]

Calculate the horizontal momentum of the water striking the wall in 1.0 s.

(b)[2]

The horizontal momentum of the water drops to zero when it reaches the wall. No water rebounds from the wall. Explain why the momentum calculated in a(ii) is equal in size to the horizontal force exerted on the water by the wall.

(c)[2]

Explain, in terms of Newton’s third law, why the water exerts a horizontal force on the wall.

(d)[1]

The pump driving the water through the hose is adjusted, and the speed of the water leaving the hose doubles. Explain why the force exerted by the water on the wall increases by a factor of 4.

Worked solution & mark scheme

This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: From $m=\rho V$, or $1000 \times 7.5 \times 10^-3$

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