Physics 5054 · O Level · Consequences of thermal energy transfer

Consequences of thermal energy transfer — practice question

A student examines how the surrounding temperature changes the rate at which water cools.
(a(i))[1]

Enter the water temperature at time $t = 0\,\text{s}$ into Table 2.1.

(a(ii))[1]

Before each temperature reading is taken, the student stirs the water in the beaker carefully. Explain why.

(a(iii))[2]

Calculate the average cooling rate $C_1$ of the water during the first $90\,\text{s}$ of the experiment. Use the values in Table 2.1 and the equation $C_1 = \frac{\theta_0 - \theta_{90}}{t}$, where $\theta_0$ is the temperature at $0\,\text{s}$, $\theta_{90}$ is the temperature at $90\,\text{s}$ and $t$ is $90\,\text{s}$. Give the unit for $C_1$.

(a(iv))[1]

Calculate the average cooling rate $C_2$ of the water during the last $90\,\text{s}$ of the experiment. Use the equation $C_2 = \frac{\theta_{150} - \theta_{240}}{t}$, where $t$ is $90\,\text{s}$.

(a(v))[1]

Compare your values of $C_1$ and $C_2$. Explain any difference between these values.

(b(i))[1]

Calculate the average cooling rate $C_3$ of the hot water for the $90\,\text{s}$. Use the readings in Table 2.2 and the equation $C_3 = \frac{\theta_0 - \theta_{90}}{t}$.

(b(ii))[1]

Describe how $C_3$ differs from $C_1$. Explain your answer.

(b(iii))[1]

The recorded readings show that this experiment is not a valid comparison of $C_1$ and $C_3$. Using the results shown in Table 2.1 and Table 2.2, explain why this comparison is not valid.

(b(iv))[1]

State one other variable that ought to be kept constant to make a valid comparison.

Worked solution & mark scheme

This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: \theta = 72 ^{\circ}C

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