Mathematics 4024 · O Level · Vector geometry

Vector geometry — practice question

$\vec{OA}=\vec{a}$ and $\vec{OB}=\vec{b}$. Point $X$ lies on $AB$ with $AX:XB=3:2$. $OXC$ forms a straight line. $AC$ is parallel to $OB$.
(a)[2]

Determine $\vec{AX}$. Express your answer in its simplest form using $\vec{a}$ and $\vec{b}$.

(b)[3]

Determine $\vec{XC}$. Express your answer in its simplest form using $\vec{a}$ and $\vec{b}$.

Worked solution & mark scheme

This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: Hence, $\vec{AX}=\frac{3}{5}(b-a)$.

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