$OCB$ forms a triangle. Point $A$ lies on $OC$ such that $OA : AC = 1 : 3$. $X$ is the midpoint of $BC$. $\vec{OA} = \mathbf{a}$ and $\vec{OB} = \mathbf{b}$.
(main)[3]
State the position vector of $X$. Express your answer in the simplest form using $\mathbf{a}$ and $\mathbf{b}$.
Worked solution & mark scheme
This 3-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Simplified answer: $2a+\tfrac12b$.” …