Mathematics 4024 · O Level · Vector geometry

Vector geometry — practice question

The diagram shows $X$ on $AB$ with $AX = \frac{1}{4}AB$, $Y$ on $AC$ with $AY = \frac{1}{3}AC$, and $Z$ on the extension of $BC$ with $CZ = 2BC$. Also, $\overrightarrow{AY} = p$ and $\overrightarrow{AX} = q$.
(a(i))[1]

Express $\overrightarrow{XY}$ using $p$ and $q$.

(a(ii))[1]

Express $\overrightarrow{BC}$ using $p$ and $q$.

(a(iii))[2]

Express $\overrightarrow{XZ}$ using $p$ and $q$.

(b)[1]

Hence, find $XY : YZ$.

Worked solution & mark scheme

This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: $p-q$

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