A, D and B lie on the same straight line, and A, E and C lie on another straight line. BC is parallel to DE. BC = $9.8\,\text{cm}$, BD = $2.7\,\text{cm}$, DE = $5.6\,\text{cm}$ and CE = $3.9\,\text{cm}$.
(a)[3]
Fill in the missing angles and reasons to demonstrate that triangle $ABC$ is similar to triangle $ADE$.
(b)[4]
Show that the lengths are $AD = 3.6\,\text{cm}$ and $AE = 5.2\,\text{cm}$.
(c)[3]
Calculate the value of angle $DAE$.
(d)[2]
Calculate the area enclosed by triangle $ABC$.
Worked solution & mark scheme
This 12-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$\angle DAE,\ \angle ADE,\ \angle AED$” …