From the diagram, triangles $APQ$ and $ABC$ are similar. Since $BC$ is parallel to $PQ$, and $AP = 4$ cm, $PB = 2$ cm and $PQ = 1.8$ cm.
(a)[2]
Find the value of $BC$.
(b)[1]
Find $\dfrac{\text{area of triangle } APQ}{\text{area of quadrilateral } PBCQ}$.
Worked solution & mark scheme
This 3-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Correct application of the similar triangles ratio” …