ANB, BLC and CMA are straight lines. $NM$ runs parallel to $BC$, and $LN$ runs parallel to $CA$.
(a)[3]
Show that triangle $ANM$ is similar to triangle $NBL$. Give a reason for every statement you write.
(b(i))[2]
$AN : NB = 2 : 3$. Determine $NM : BC$.
(b(ii))[1]
Determine $\text{area } ANM : \text{area } NBL$.
(b(iii))[2]
Determine $\text{area } ANM : \text{area } NMCL$.
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