$ABCD$ is a field. Its sides are $AB = 320\text{ m}$, $BC = 250\text{ m}$, $CD = 132\text{ m}$ and $AD = 365\text{ m}$. Angle $BCD = 90^\circ$.
(a)[3]
Ray travels from $A$ to $B$ with an average speed of $1.6\text{ m/s}$. He then continues from $B$ to $C$ with an average speed of $2.8\text{ m/s}$. Calculate Ray’s average speed for the journey from $A$ to $B$ to $C$.
(b)[5]
The bearing of $D$ from $A$ is $243^\circ$. Calculate the bearing of $B$ from $A$.
Worked solution & mark scheme
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “The answer is $1.97$.” …