$A$ lies at $(3,11)$ and $B$ lies at $(-5,-5)$. Line $L$ has equation $2y + x = 5$.
(main)[5]
Show that $L$ is the perpendicular bisector of $AB$.
Worked solution & mark scheme
This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: “The midpoint of $AB$ comes out as $(-1,3)$” …
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