(a)[1]
Calculate the difference between $3\frac{1}{6}$ and $\sqrt{10}$. State your answer correct to 2 significant figures.
(b)[1]
Estimate, to the nearest whole number, the value of $\sqrt{2.986^2+4.002^2}$.
Mathematics 4024 · O Level · Limits of accuracy
Limits of accuracy — practice question
To 6 decimal places, $\sqrt{10}=3.162278$, whereas $3\frac{1}{6}=3.166667$.