A rectangle and a triangle are shown in the diagram. The rectangle’s length is x cm, and its area is 30 cm^{2}. The triangle’s sides measure (x-1) cm, (x+2) cm and (2x-3) cm.
(a)[1]
Express the width of the rectangle in terms of x.
(b)[4]
Set the rectangle’s perimeter equal to the triangle’s perimeter. Form an equation in x and show that it reduces to $x^2-x-30=0$.
(c)[3]
Solve $x^2-x-30=0$.
(d)[2]
Find the perimeter of the rectangle.
Worked solution & mark scheme
This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$30/x$” …