$\begin{pmatrix} x & 3 \\ 2 & x+1 \end{pmatrix} \begin{pmatrix} x-1 \\ 2 \end{pmatrix} = \begin{pmatrix} 2x+6 \\ y \end{pmatrix}$.
(a)[2]
Show that $x^2 - 3x = 0$.
(b(i))[2]
Solve $x^2 - 3x = 0$.
(b(ii))[2]
Find $y$ when $x > 0$.
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