The circles centred at $O$ and $Q$ are shown touching at $P$, with $OPQ$ lying on one straight line. The straight line $ORT$ cuts the smaller circle at $R$ and is a tangent to the larger circle at $T$. $OR = 4\,\text{cm}$ and $RT = 6\,\text{cm}$. The radius of the larger circle is $x\,\text{cm}$.
(main)[4]
Calculate $x$.
Worked solution & mark scheme
This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$10.5$” …