(a)[3]
Solve $\frac{y}{2y + 3} = \frac{2}{y + 5}$.
(b)[3]
Make $t$ the subject in the formula $p = \frac{4t + 1}{2 - t}$.
(c)[3]
Simplify fully the expression $\frac{3x^2 - 14x + 8}{x^2 - 16}$.
Mathematics 4024 · O Level · Algebraic fractions
Solve $\frac{y}{2y + 3} = \frac{2}{y + 5}$.
Make $t$ the subject in the formula $p = \frac{4t + 1}{2 - t}$.
Simplify fully the expression $\frac{3x^2 - 14x + 8}{x^2 - 16}$.