The equation represents how iron is obtained when iron(III) oxide is reduced. $\text{Fe}_2\text{O}_3 + 3\text{CO} \rightarrow 2\text{Fe} + 3\text{CO}_2$ 80 tonnes of iron(III) oxide gives 50 tonnes of iron. Calculate the percentage yield?
- A45%
- B63%
- C68%
- D89%