The equation represents iron being formed when iron(III) oxide is reduced. $\text{Fe}_2\text{O}_3 + 3\text{CO} \rightarrow 2\text{Fe} + 3\text{CO}_2$. $80$ tonnes of iron(III) oxide gives $50$ tonnes of iron. Calculate the percentage yield.
- A45%
- B63%
- C68%
- D89%