The equation below shows aqueous sodium hydroxide being neutralised by dilute sulfuric acid. $2\text{NaOH}(aq) + \text{H}_2\text{SO}_4(aq) \rightarrow \text{Na}_2\text{SO}_4(aq) + 2\text{H}_2\text{O}(l)$ What volume of sulfuric acid must be used to neutralise $100\,\text{cm}^3$ of $1.0\,\text{mol dm}^{-3}$ NaOH?
- A$50\,\text{cm}^3$ of $2.0\,\text{mol dm}^{-3}$ sulfuric acid
- B$100\,\text{cm}^3$ of $1.0\,\text{mol dm}^{-3}$ sulfuric acid
- C$25\,\text{cm}^3$ of $0.5\,\text{mol dm}^{-3}$ sulfuric acid
- D$50\,\text{cm}^3$ of $1.0\,\text{mol dm}^{-3}$ sulfuric acid