A $100\,\text{cm}^3$ portion of aqueous potassium hydroxide, with a concentration of $1.00\,\text{mol dm}^{-3}$, is reacted with excess dilute sulfuric acid. $2\text{KOH}(aq) + \text{H}_2\text{SO}_4(aq) \rightarrow \text{K}_2\text{SO}_4(aq) + 2\text{H}_2\text{O}(l)$ A mass of $3.48\,\text{g}$ of pure anhydrous potassium sulfate is obtained. Calculate the percentage yield of potassium sulfate.
- A5%
- B10%
- C20%
- D40%