The reaction equation for ammonium chloride with calcium hydroxide is given below. $\text{2NH}_4\text{Cl} + \text{Ca(OH)}_2 \rightarrow 2\text{NH}_3 + \text{CaCl}_2 + 2\text{H}_2\text{O}$ $10.7\,\text{g}$ of ammonium chloride and $14.8\,\text{g}$ of calcium hydroxide are combined and heated. The mass of calcium chloride formed is $10.0\,\text{g}$. Calculate the percentage yield of calcium chloride. $[M_r: \text{NH}_4\text{Cl},\,53.5;\ \text{Ca(OH)}_2,\,74;\ \text{CaCl}_2,\,111]$
- A$39.2\%$
- B$45.0\%$
- C$67.6\%$
- D$90.1\%$