(a(i))[1]
Suggest why a crucible is preferred to a glass beaker.
(a(ii))[1]
Suggest why steps 3 and 4 are carried out again until the same mass is recorded twice.
(b(i))[1]
Complete the missing entries in the table.
(b(ii))[2]
On the grid, plot the final mass of MgSO$_4$ versus the mass of H$_2$O lost.
(b(iii))[1]
Circle the anomalous result on the graph.
(b(iv))[1]
Suggest why this result is anomalous.
(b(v))[1]
Draw a straight best-fit line.
(c(i))[1]
In another experiment, the final mass of MgSO$_4$ is $1.20\,\text{g}$. Use your graph to work out the mass of H$_2$O lost.
(c(ii))[2]
Calculate the number of moles of water in the result from (i). [$A_r$: H, 1; O, 16]
(c(iii))[1]
$1.20\,\text{g}$ of MgSO$_4$ corresponds to $0.01\,\text{mol}$ of MgSO$_4$. Determine the value of $x$ in MgSO$_4\cdot x$H$_2$O.