To prepare calcium nitrate, a chemist reacts $8.00\text{ g}$ of pure calcium oxide with an excess of dilute nitric acid. The reaction gives $12.65\text{ g}$ of pure, dry anhydrous calcium nitrate crystals. Calculate the percentage yield of calcium nitrate. [relative atomic mass values, $A_r$: Ca, $40$; N, $14$; H, $1$; O, $16$]
- A$54.0$
- B$63.2$
- C$67.1$
- D$86.8$