The equation for turning bromoethane into ethanol is given below. $\text{C}_2\text{H}_5\text{Br} + \text{NaOH} \rightarrow \text{C}_2\text{H}_5\text{OH} + \text{NaBr}$ During an experiment, $10.90\,\text{g}$ of bromoethane is changed into $3.45\,\text{g}$ of ethanol. Calculate the percentage yield of ethanol. $[M_r:\ \text{C}_2\text{H}_5\text{Br},\ 109;\ \text{C}_2\text{H}_5\text{OH},\ 46]$
- A$32\%$
- B$42\%$
- C$75\%$
- D$100\%$