Chemistry 5070 · O Level · The mole and the Avogadro constant

The mole and the Avogadro constant — practice question

A scientist has to work out which metal ion is present in a metal carbonate, $MCO_3$. The $MCO_3$ is heated in a crucible, and it decomposes to produce $MO$ and $CO_2$.
(a)[2]

Give two reasons for fitting the crucible with the lid in a loose position.

(b)[2]

Fill in the results table.

(c)[1]

The crucible is heated for a further three minutes. The mass of the crucible, lid and contents is $11.5\text{ g}$. Explain why this is different from the value in the table.

(d)[1]

The total mass of carbon dioxide, $CO_2$, formed is $1.1\text{ g}$. Calculate the number of moles of $CO_2$ formed. $[M_r: CO_2 = 44]$

(e)[1]

The decomposition equation for the metal carbonate is given as $MCO_3 \rightarrow MO + CO_2$. Use this equation together with your answers to (b) and (d) to calculate the relative formula mass of $MCO_3$.

(f)[1]

Calculate the relative atomic mass, $A_r$, of metal $M$. $[A_r: C, 12; O, 16]$

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: Prevents solid / MCO₃ / MO from escaping

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