The equation represents a reaction in the Contact process. $2\text{SO}_2(g) + \text{O}_2(g) \rightleftharpoons 2\text{SO}_3(g) \quad \Delta H = -196\,\text{kJ mol}^{-1}$ Which change would shift the equilibrium position to the left?
- Aadding more $\text{O}_2$
- Bincreasing the pressure
- Cincreasing the temperature
- Dremoving $\text{SO}_3$ from the reacting mixture