Chemistry 5070 · O Level · Reversible reactions and equilibrium

Reversible reactions and equilibrium — practice question

Sodium is a Group I metal in the Periodic Table. Diamond (carbon) is a non-metal and it conducts heat well.
(a)[2]

State two physical-property differences between sodium and diamond.

(b)[3]

A sodium ion has the symbol $^{23}_{11}\text{Na}^+$. Deduce how many protons, neutrons and electrons are present in this ion.

(c)[1]

Sodium combines with nitrogen to form sodium nitride. Complete the equation for this reaction. $\ldots\,\text{Na} + \ldots \rightarrow \ldots\,\text{Na}_3\text{N}$

(d(i))[2]

When carbon is heated with steam inside a closed container, an equilibrium mixture is established. $\text{C(s)} + \text{H}_2\text{O(g)} \rightleftharpoons \text{CO(g)} + \text{H}_2\text{(g)}$ The forward reaction is endothermic. Describe and explain the effect, if any, on the position of equilibrium when the temperature is increased.

(d(ii))[2]

Describe and explain, if there is any effect, how the position of equilibrium changes when the pressure is lowered.

Worked solution & mark scheme

This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: sodium conducts electricity / diamond is non-conducting

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