Sulfur trioxide is formed by the reaction shown here. $2\text{SO}_2\text{(g)} + \text{O}_2\text{(g)} \rightleftharpoons 2\text{SO}_3\text{(g)} \quad \Delta H = -195\,\text{kJ}$ Which change in conditions would give a larger amount of $\text{SO}_3$ at equilibrium?
- Aadding a catalyst
- Bincreasing the pressure
- Cincreasing the temperature
- Dremoving some $\text{SO}_2$ and $\text{O}_2$