Chemistry 5070 · O Level · Reversible reactions and equilibrium

Reversible reactions and equilibrium — practice question

Ozone molecules are constantly broken apart and rebuilt in the upper atmosphere.
(a(i))[2]

The equation gives one route by which ozone is formed in the upper atmosphere: $\text{O}_2 + \text{O} \rightarrow \text{O}_3\quad \Delta H = -392\,\text{kJ mol}^{-1}$. Explain, in terms of bond breaking and bond forming, why this reaction is exothermic.

(a(ii))[2]

When 1 mole of oxygen molecules reacts, 392 kJ of energy is given out. Calculate the amount of energy released when 48.0 g of oxygen molecules react.

(b)[1]

Name a pollutant that destroys ozone in the upper atmosphere.

(c(i))[2]

Ozone molecules decompose into oxygen molecules in a reversible reaction: $2\text{O}_3(\text{g}) \rightleftharpoons 3\text{O}_2(\text{g})\quad \Delta H = +143\,\text{kJ mol}^{-1}$. The reaction is studied at a temperature of $400^\circ\text{C}$. Describe and explain what happens to the position of equilibrium if the pressure is increased.

(c(ii))[2]

The reaction is studied at 25 atmospheres pressure. Describe and explain what happens to the position of equilibrium if the temperature is decreased.

(c(iii))[2]

Describe and explain what will happen to the rate of the reaction if the temperature is decreased.

Worked solution & mark scheme

This 11-mark question has a full step-by-step worked solution and mark scheme. One marking point: Energy is absorbed when bonds are broken; energy is released when bonds are made

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