A student puts the catalyst manganese(IV) oxide into aqueous hydrogen peroxide, and the hydrogen peroxide breaks down: $\text{2H}_2\text{O}_2(aq) \rightarrow \text{2H}_2\text{O}(l) + \text{O}_2(g)$. The student then measures the volume of oxygen released at regular time intervals. This is experiment 1. The student carries out experiment 2 again, but with one altered condition. Graphs for experiments 1 and 2 are shown.
(main)[1]
Which condition is changed in experiment 2?
Worked solution & mark scheme
This 1-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Option B” …