In aqueous solution, peroxodisulfate ions, S$_2$O$_8^{2-}$, react with iodide ions.
S$_2$O$_8^{2-}$(aq) + 2I$^-$(aq) $\rightarrow$ 2SO$_4^{2-}$(aq) + I$_2$(aq)
The table displays how the relative rate of this reaction varies when different concentrations of peroxodisulfate ions and iodide ions are used.
(a)[2]
Use the table to describe the effect of increasing the concentration of each ion on the relative rate of reaction.
peroxodisulfate ions
iodide ions
(b)[1]
Iron(III) ions, Fe$^{3+}$, catalyse this reaction. Explain how catalysts speed up a reaction.
(c(i))[1]
Explain how iron(III) ions function as an oxidising agent in this reaction.
2I$^-$(aq) + 2Fe$^{3+}$(aq) $\rightarrow$ I$_2$(aq) + 2Fe$^{2+}$(aq)
(c(ii))[1]
What colour change is seen when this reaction takes place?
(c(iii))[2]
Describe a test for iron(III) ions.
test used
observation made
(d)[1]
Iron(II) ions react with peroxodisulfate ions to form iron(III) ions and sulfate ions. Construct the equation for this reaction.
Worked solution & mark scheme
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “peroxodisulfate: when concentration is doubled, the rate also doubles” …