Chemistry 5070 · O Level · Rate of reaction

Rate of reaction — practice question

In aqueous solution, peroxodisulfate ions, S$_2$O$_8^{2-}$, react with iodide ions. S$_2$O$_8^{2-}$(aq) + 2I$^-$(aq) $\rightarrow$ 2SO$_4^{2-}$(aq) + I$_2$(aq) The table displays how the relative rate of this reaction varies when different concentrations of peroxodisulfate ions and iodide ions are used.
(a)[2]

Use the table to describe the effect of increasing the concentration of each ion on the relative rate of reaction. peroxodisulfate ions iodide ions

(b)[1]

Iron(III) ions, Fe$^{3+}$, catalyse this reaction. Explain how catalysts speed up a reaction.

(c(i))[1]

Explain how iron(III) ions function as an oxidising agent in this reaction. 2I$^-$(aq) + 2Fe$^{3+}$(aq) $\rightarrow$ I$_2$(aq) + 2Fe$^{2+}$(aq)

(c(ii))[1]

What colour change is seen when this reaction takes place?

(c(iii))[2]

Describe a test for iron(III) ions. test used observation made

(d)[1]

Iron(II) ions react with peroxodisulfate ions to form iron(III) ions and sulfate ions. Construct the equation for this reaction.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: peroxodisulfate: when concentration is doubled, the rate also doubles

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