A $2\ \text{g}$ portion of calcium carbonate reacts with dilute hydrochloric acid, as shown. $\text{CaCO}_3\text{(s)} + 2\text{HCl(aq)} \rightarrow \text{CaCl}_2\text{(aq)} + \text{CO}_2\text{(g)} + \text{H}_2\text{O(l)}$ Which alteration in conditions causes the reaction to take place more slowly?
- Aincreasing the acid concentration
- Bincreasing the size of the solid particles
- Cincreasing the surface area of the solid particles
- Dincreasing the temperature