Chemistry 5070 · O Level · Formulae, functional groups and terminology

Formulae, functional groups and terminology — practice question

Fig. 8.1 presents the displayed formula for compound A.
(a(i))[1]

Compound A belongs to both the saturated alcohol and saturated ester groups. Explain why compound A is saturated.

(a(ii))[1]

Explain why compound A is classified as an alcohol.

(a(iii))[1]

Explain why compound A should be identified as an ester.

(b)[1]

Fig. 8.2 presents compound B. Explain why compound A and compound B form a pair of structural isomers.

(c(i))[1]

The displayed formula for compound C appears in Fig. 8.3. Compound C is an ester. Compound C is formed by reacting an alcohol with a carboxylic acid in the presence of a catalyst. State the name of the type of catalyst used in this reaction.

(c(ii))[2]

State the name of the alcohol used in this reaction and draw its displayed formula.

(d(i))[2]

Fig. 8.4 presents two monomers that combine to form a condensation polymer. Draw the structure of one repeat unit of this condensation polymer.

(d(ii))[1]

Equal numbers of moles of monomers D and E are used to make the condensation polymer. The combined mass of monomers D and E is 80 g. The yield is 100%. Explain why the mass of the condensation polymer made is less than 80 g.

Worked solution & mark scheme

This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: Every carbon-carbon bond is a single bond

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