Chemistry 5070 · O Level · Exothermic and endothermic reactions

Exothermic and endothermic reactions — practice question

A student examines how concentration affects the energy change in a neutralisation reaction. The student: - measures out $25.0\,\text{cm}^3$ of aqueous sodium hydroxide, $\text{NaOH(aq)}$, into a beaker - takes the temperature of this solution - pours $25.0\,\text{cm}^3$ of $0.10\,\text{mol dm}^{-3}$ hydrochloric acid, $\text{HCl(aq)}$, into the beaker - stirs the mixture - records the highest temperature reached by the solution in the beaker - repeats the experiment using different concentrations of hydrochloric acid.
(a)[2]

The diagram shows the highest temperatures reached for $0.10\,\text{mol dm}^{-3}$ and $0.50\,\text{mol dm}^{-3}$ $\text{HCl(aq)}$. The starting temperature of $\text{NaOH(aq)}$ and the $\text{HCl(aq)}$ in every experiment is $20.0\,^{\circ}\text{C}$. Fill in the table with the highest temperatures and the temperature changes.

(b)[1]

The temperature change for $0.70\,\text{mol dm}^{-3}$ $\text{HCl(aq)}$ is anomalous. Suggest what the student should do to check that this temperature change is anomalous.

(c)[2]

Plot temperature change on the y-axis against $\text{HCl(aq)}$ concentration on the x-axis on the grid.

(d)[2]

Draw one straight line of best fit for concentrations up to $0.90\,\text{mol dm}^{-3}$ and a second straight line through the other three points. Extend both straight lines until they meet.

(e)[1]

Use the graph to find the concentration of $\text{HCl(aq)}$ that gives a temperature change of $5.4\,^{\circ}\text{C}$.

(f)[1]

Use the graph to find the temperature change for $1.40\,\text{mol dm}^{-3}$ $\text{HCl(aq)}$.

(g)[1]

Use the graph to find the minimum concentration of $\text{HCl(aq)}$ needed to neutralise all the $\text{NaOH(aq)}$.

(h)[1]

Heat loss is a major source of error in this experiment. Suggest how the student can cut down the heat loss.

Worked solution & mark scheme

This 11-mark question has a full step-by-step worked solution and mark scheme. One marking point: 20.8 at 0.100 mol/dm^{3} AND 23.6 at 0.500 mol/dm^{3}

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