During a titration, a $25.0\,\text{cm}^3$ portion of $0.100\,\text{mol dm}^{-3}$ sodium hydroxide is neutralised exactly by $16.2\,\text{cm}^3$ of dilute sulfuric acid. The reaction equation is given below. $\text{H}_2\text{SO}_4 + 2\text{NaOH} \rightarrow \text{Na}_2\text{SO}_4 + 2\text{H}_2\text{O}$ Calculate the concentration of the dilute sulfuric acid.
- A$0.0648\,\text{mol dm}^{-3}$
- B$0.0772\,\text{mol dm}^{-3}$
- C$0.154\,\text{mol dm}^{-3}$
- D$0.309\,\text{mol dm}^{-3}$