A copper container with mass $0.20\,\text{kg}$ holds $0.10\,\text{kg}$ of water. The specific heat capacity of copper is $385\,\text{J (kg}^{-1}\,^{\circ}\text{C}^{-1})$ and the specific heat capacity of water is $4200\,\text{J (kg}^{-1}\,^{\circ}\text{C}^{-1})$. Calculate the energy, in joules, required to increase the temperature of the copper container and the water by $10^{\circ}\text{C}$?
- A$(0.20 \times 385 \times 10) - (0.10 \times 4200 \times 10)$
- B$(0.20 \times 385 \times 10) + (0.10 \times 4200 \times 10)$
- C$(0.10 + 0.20) \times \left(\frac{4200 + 385}{2}\right) \times 10$
- D$(0.10 + 0.20) \times (4200 + 385) \times 10$