An americium atom’s nucleus contains 146 neutrons and 95 protons. It decays by releasing an $\alpha$-particle. After this type of americium decay, how many neutrons and how many protons are left in the nucleus?
- A142 neutrons, 93 protons
- B142 neutrons, 95 protons
- C144 neutrons, 93 protons
- D144 neutrons, 95 protons