Carbon-14 has proton number $(Z)$ $6$ and nucleon number $(A)$ $14$. Nitrogen-14 has proton number $7$ and nucleon number $14$. Carbon-14 decays by emitting $\beta$-particles to produce nitrogen-14. Which nuclide equation represents this process?
- A$^{14}_{6}\text{C} \rightarrow ^{14}_{7}\text{N} + ^{0}_{1}\beta$
- B$^{14}_{6}\text{C} \rightarrow ^{14}_{7}\text{N} + ^{0}_{0}\beta$
- C$^{14}_{6}\text{C} \rightarrow ^{14}_{7}\text{N} + ^{0}_{-1}\beta$
- D$^{6}_{14}\text{C} \rightarrow ^{7}_{14}\text{N} + ^{0}_{-1}\beta$