A nucleus of americium $^{243}_{95}\text{Am}$ releases an $\alpha$-particle, producing a nucleus of neptunium (Np). Which equation describes this decay?
- A$^{243}_{95}\text{Am} \rightarrow ^{247}_{97}\text{Np} + ^{4}_{2}\alpha$
- B$^{243}_{95}\text{Am} \rightarrow ^{243}_{96}\text{Np} + ^{0}_{-1}\alpha$
- C$^{243}_{95}\text{Am} \rightarrow ^{243}_{94}\text{Np} + ^{0}_{-1}\alpha$
- D$^{243}_{95}\text{Am} \rightarrow ^{239}_{93}\text{Np} + ^{4}_{2}\alpha$