Physics 0625 · IGCSE · Motion

Motion — practice question

A car speeds up uniformly along a straight line starting from rest at time $t = 0$. By $t = 3.2\,\text{s}$, its speed is $13.0\,\text{m s}^{-1}$.
(a(i))[2]

Calculate the car's acceleration.

(a(ii))[1]

Explain in words what the term acceleration means.

(b(i))[2]

Plot the car’s speed-time graph from $t = 0$ to $t = 12.0\,\text{s}$.

(b(ii))[2]

Determine the distance covered by the car between $t = 0$ and $t = 3.2\,\text{s}$.

(c)[4]

Show that the work done by the car during deceleration is about $1.1 \times 10^5\,\text{J}$.

(d)[2]

Suggest and explain what makes the stopping distance increase.

Worked solution & mark scheme

This 13-mark question has a full step-by-step worked solution and mark scheme. One marking point: $4.1\,\text{m s}^{-2}$

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