The beam is hinged at one end, as the diagram shows. Its weight is $6.0\,\text{N}$, and this weight acts at point X, which is $40\,\text{cm}$ from the pivot. A force of $4.0\,\text{N}$ is applied to the beam so that it stays balanced horizontally. In what direction, and at what position, is the $4.0\,\text{N}$ force applied?
- Avertically downwards at $20\,\text{cm}$ to the left of X
- Bvertically downwards at $20\,\text{cm}$ to the right of X
- Cvertically upwards at $20\,\text{cm}$ to the left of X
- Dvertically upwards at $20\,\text{cm}$ to the right of X