A beam is pivoted at one end, as shown. Its weight is $6.0\,\text{N}$ and acts at point $X$, which is $40\,\text{cm}$ from the pivot. A force of $4.0\,\text{N}$ is exerted on the beam so that it remains balanced in a horizontal position. In what direction is the $4.0\,\text{N}$ force applied, and at what point does it act?
- Adownwards at $20\,\text{cm}$ to the left of $X$
- Bdownwards at $20\,\text{cm}$ to the right of $X$
- Cupwards at $20\,\text{cm}$ to the left of $X$
- Dupwards at $20\,\text{cm}$ to the right of $X$