Two people $X$ and $Y$ are seated on a see-saw, as illustrated. $X$ has a weight of $400\,\text{N}$ and is positioned $1.5\,\text{m}$ from the pivot. The see-saw itself weighs $300\,\text{N}$ and its weight acts through the pivot. With the see-saw in balance, the pivot exerts an upward force of $900\,\text{N}$ on the see-saw. Determine the weight of person $Y$ and the distance from the pivot at which he is seated?
- Aweight of $Y = 200\,\text{N}$, distance from pivot $= 1.5\,\text{m}$
- Bweight of $Y = 200\,\text{N}$, distance from pivot $= 3.0\,\text{m}$
- Cweight of $Y = 400\,\text{N}$, distance from pivot $= 1.5\,\text{m}$
- Dweight of $Y = 400\,\text{N}$, distance from pivot $= 3.0\,\text{m}$