Mathematics 0580 · IGCSE · Vectors in two dimensions

Vectors in two dimensions — practice question

The diagram depicts triangle $OAB$ together with parallelogram $OALK$. The position vector of $A$ is $\mathbf{a}$ and the position vector of $B$ is $\mathbf{b}$. Point $K$ lies on $AB$ so that $AK : KB = 1 : 2$. Sketch NOT TO SCALE.
(main)[4]

Determine the position vector of $L$ in terms of $\mathbf{a}$ and $\mathbf{b}$. Write your answer in its simplest form.

Worked solution & mark scheme

This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: Either $\overrightarrow{AK}=-\frac{1}{3}a+\frac{1}{3}b$ or $\overrightarrow{BK}=\frac{2}{3}a-\frac{2}{3}b$

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